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-x^2+25x-33=0
We add all the numbers together, and all the variables
-1x^2+25x-33=0
a = -1; b = 25; c = -33;
Δ = b2-4ac
Δ = 252-4·(-1)·(-33)
Δ = 493
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{493}}{2*-1}=\frac{-25-\sqrt{493}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{493}}{2*-1}=\frac{-25+\sqrt{493}}{-2} $
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